Today I have done leetcode's November LeetCoding Challenge with cpp.

November LeetCoding Challenge 8

Description

Minimum One Bit Operations to Make Integers Zero

Given an integer n, you must transform it into 0 using the following operations any number of times:

• Change the rightmost (0th) bit in the binary representation of n.
• Change the ith bit in the binary representation of n if the (i-1)th bit is set to 1 and the (i-2)th through 0th bits are set to 0.

Return the minimum number of operations to transform n into 0.

Example 1:

Input: n = 3
Output: 2
Explanation: The binary representation of 3 is "11".
"11" -> "01" with the 2nd operation since the 0th bit is 1.
"01" -> "00" with the 1st operation.

Example 2:

Input: n = 6
Output: 4
Explanation: The binary representation of 6 is "110".
"110" -> "010" with the 2nd operation since the 1st bit is 1 and 0th through 0th bits are 0.
"010" -> "011" with the 1st operation.
"011" -> "001" with the 2nd operation since the 0th bit is 1.
"001" -> "000" with the 1st operation.

Constraints:

• 0 <= n <= 109

Solution

class Solution {
public:
  int minimumOneBitOperations(int n) {
    int res = 0;
    while(n > 0) {
      res = -(res + (n ^ (n - 1)));
      n &= n - 1;
    }
    return abs(res);
  }
};

// Accepted
// 308/308 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 55.27 % of cpp submissions (8.1 MB)