2025-06-15 Daily Challenge
Today I have done leetcode's June LeetCoding Challenge with cpp.
June LeetCoding Challenge 15
Description
Max Difference You Can Get From Changing an Integer
You are given an integer num. You will apply the following steps to num two separate times:
- Pick a digit
x (0 <= x <= 9). - Pick another digit
y (0 <= y <= 9). Noteycan be equal tox. - Replace all the occurrences of
xin the decimal representation ofnumbyy.
Let a and b be the two results from applying the operation to num independently.
Return the max difference between a and b.
Note that neither a nor b may have any leading zeros, and must not be 0.
Example 1:
Input: num = 555 Output: 888 Explanation: The first time pick x = 5 and y = 9 and store the new integer in a. The second time pick x = 5 and y = 1 and store the new integer in b. We have now a = 999 and b = 111 and max difference = 888
Example 2:
Input: num = 9 Output: 8 Explanation: The first time pick x = 9 and y = 9 and store the new integer in a. The second time pick x = 9 and y = 1 and store the new integer in b. We have now a = 9 and b = 1 and max difference = 8
Constraints:
1 <= num <= 108
Solution
class Solution {
public:
int maxDiff(int num) {
string n = to_string(num);
string maxN = n;
int len = n.length();
int start = 0;
while(start < len && maxN[start] == '9') start += 1;
for(int i = start + 1; i < len; ++i) {
if(maxN[i] == maxN[start]) maxN[i] = '9';
}
if(start < len) maxN[start] = '9';
string minN = n;
bool changed = false;
for(int i = 0; i < len && !changed; ++i) {
char target = minN[i];
if(!i) {
if(target == '1') continue;
changed = true;
for(int j = 0; j < len; ++j) {
if(minN[j] == target) minN[j] = '1';
}
} else {
if(target == '0' || target == minN[0]) continue;
changed = true;
for(int j = 0; j < len; ++j) {
if(minN[j] == target) minN[j] = '0';
}
}
}
return stoi(maxN) - stoi(minN);
}
};
// Accepted
// 211/211 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 66.9 % of cpp submissions (8.2 MB)