2025-05-25 Daily Challenge
Today I have done leetcode's May LeetCoding Challenge with cpp
.
May LeetCoding Challenge 25
Description
Longest Palindrome by Concatenating Two Letter Words
You are given an array of strings words
. Each element of words
consists of two lowercase English letters.
Create the longest possible palindrome by selecting some elements from words
and concatenating them in any order. Each element can be selected at most once.
Return the length of the longest palindrome that you can create. If it is impossible to create any palindrome, return 0
.
A palindrome is a string that reads the same forward and backward.
Example 1:
Input: words = ["lc","cl","gg"] Output: 6 Explanation: One longest palindrome is "lc" + "gg" + "cl" = "lcggcl", of length 6. Note that "clgglc" is another longest palindrome that can be created.
Example 2:
Input: words = ["ab","ty","yt","lc","cl","ab"] Output: 8 Explanation: One longest palindrome is "ty" + "lc" + "cl" + "yt" = "tylcclyt", of length 8. Note that "lcyttycl" is another longest palindrome that can be created.
Example 3:
Input: words = ["cc","ll","xx"] Output: 2 Explanation: One longest palindrome is "cc", of length 2. Note that "ll" is another longest palindrome that can be created, and so is "xx".
Constraints:
1 <= words.length <= 105
words[i].length == 2
words[i]
consists of lowercase English letters.
Solution
auto speedup = [](){
cin.tie(nullptr);
cout.tie(nullptr);
ios::sync_with_stdio(false);
return 0;
}();
class Solution {
public:
int longestPalindrome(vector<string>& words) {
int count[26][26] = {};
int answer = 0;
for(const auto &word : words) {
int a = word[0] - 'a';
int b = word[1] - 'a';
if(count[b][a]) {
answer += 4;
count[b][a] -= 1;
} else {
count[a][b] += 1;
}
}
for(int i = 0; i < 26 ; ++i) {
if(count[i][i]) {
answer += 2;
break;
}
}
return answer;
}
};
// Accepted
// 120/120 cases passed (7 ms)
// Your runtime beats 97.74 % of cpp submissions
// Your memory usage beats 99.38 % of cpp submissions (171.4 MB)