2025-05-01 Daily Challenge

Today I have done leetcode's May LeetCoding Challenge with cpp.

May LeetCoding Challenge 1

Description

Maximum Number of Tasks You Can Assign

You have n tasks and m workers. Each task has a strength requirement stored in a 0-indexed integer array tasks, with the ith task requiring tasks[i] strength to complete. The strength of each worker is stored in a 0-indexed integer array workers, with the jth worker having workers[j] strength. Each worker can only be assigned to a single task and must have a strength greater than or equal to the task's strength requirement (i.e., workers[j] >= tasks[i]).

Additionally, you have pills magical pills that will increase a worker's strength by strength. You can decide which workers receive the magical pills, however, you may only give each worker at most one magical pill.

Given the 0-indexed integer arrays tasks and workers and the integers pills and strength, return the maximum number of tasks that can be completed.

 

Example 1:

Input: tasks = [3,2,1], workers = [0,3,3], pills = 1, strength = 1
Output: 3
Explanation:
We can assign the magical pill and tasks as follows:
- Give the magical pill to worker 0.
- Assign worker 0 to task 2 (0 + 1 >= 1)
- Assign worker 1 to task 1 (3 >= 2)
- Assign worker 2 to task 0 (3 >= 3)

Example 2:

Input: tasks = [5,4], workers = [0,0,0], pills = 1, strength = 5
Output: 1
Explanation:
We can assign the magical pill and tasks as follows:
- Give the magical pill to worker 0.
- Assign worker 0 to task 0 (0 + 5 >= 5)

Example 3:

Input: tasks = [10,15,30], workers = [0,10,10,10,10], pills = 3, strength = 10
Output: 2
Explanation:
We can assign the magical pills and tasks as follows:
- Give the magical pill to worker 0 and worker 1.
- Assign worker 0 to task 0 (0 + 10 >= 10)
- Assign worker 1 to task 1 (10 + 10 >= 15)
The last pill is not given because it will not make any worker strong enough for the last task.

 

Constraints:

  • n == tasks.length
  • m == workers.length
  • 1 <= n, m <= 5 * 104
  • 0 <= pills <= m
  • 0 <= tasks[i], workers[j], strength <= 109

Solution

class Solution {
public:
  int maxTaskAssign(vector<int>& tasks, vector<int>& workers, int pills, int strength) {
    sort(tasks.begin(), tasks.end());
    sort(workers.begin(), workers.end());
    
    int low = 0;
    int high = min(tasks.size(), workers.size());
    while(low < high) {
      int mid = (low + high + 1) / 2;
      int used = 0;
      multiset<int> freed(workers.end() - mid, workers.end());

      bool can = true;
      for(int i = mid - 1; i >= 0 && can && used <= pills; --i) {
        auto it = prev(freed.end());

        if(*it < tasks[i]) {
          it = freed.lower_bound(tasks[i] - strength);

          if(it == freed.end()) {
            can = false;
          }
          used += 1;
        }
        if(can && used <= pills) freed.erase(it);
      }

      if(can && used <= pills) {
        low = mid;
      } else {
        high = mid - 1;
      }
    }
    return low;
  }
};

// Accepted
// 49/49 cases passed (661 ms)
// Your runtime beats 66.67 % of cpp submissions
// Your memory usage beats 83.33 % of cpp submissions (285.8 MB)