2025-05-01 Daily Challenge
Today I have done leetcode's May LeetCoding Challenge with cpp
.
May LeetCoding Challenge 1
Description
Maximum Number of Tasks You Can Assign
You have n
tasks and m
workers. Each task has a strength requirement stored in a 0-indexed integer array tasks
, with the ith
task requiring tasks[i]
strength to complete. The strength of each worker is stored in a 0-indexed integer array workers
, with the jth
worker having workers[j]
strength. Each worker can only be assigned to a single task and must have a strength greater than or equal to the task's strength requirement (i.e., workers[j] >= tasks[i]
).
Additionally, you have pills
magical pills that will increase a worker's strength by strength
. You can decide which workers receive the magical pills, however, you may only give each worker at most one magical pill.
Given the 0-indexed integer arrays tasks
and workers
and the integers pills
and strength
, return the maximum number of tasks that can be completed.
Example 1:
Input: tasks = [3,2,1], workers = [0,3,3], pills = 1, strength = 1 Output: 3 Explanation: We can assign the magical pill and tasks as follows: - Give the magical pill to worker 0. - Assign worker 0 to task 2 (0 + 1 >= 1) - Assign worker 1 to task 1 (3 >= 2) - Assign worker 2 to task 0 (3 >= 3)
Example 2:
Input: tasks = [5,4], workers = [0,0,0], pills = 1, strength = 5 Output: 1 Explanation: We can assign the magical pill and tasks as follows: - Give the magical pill to worker 0. - Assign worker 0 to task 0 (0 + 5 >= 5)
Example 3:
Input: tasks = [10,15,30], workers = [0,10,10,10,10], pills = 3, strength = 10 Output: 2 Explanation: We can assign the magical pills and tasks as follows: - Give the magical pill to worker 0 and worker 1. - Assign worker 0 to task 0 (0 + 10 >= 10) - Assign worker 1 to task 1 (10 + 10 >= 15) The last pill is not given because it will not make any worker strong enough for the last task.
Constraints:
n == tasks.length
m == workers.length
1 <= n, m <= 5 * 104
0 <= pills <= m
0 <= tasks[i], workers[j], strength <= 109
Solution
class Solution {
public:
int maxTaskAssign(vector<int>& tasks, vector<int>& workers, int pills, int strength) {
sort(tasks.begin(), tasks.end());
sort(workers.begin(), workers.end());
int low = 0;
int high = min(tasks.size(), workers.size());
while(low < high) {
int mid = (low + high + 1) / 2;
int used = 0;
multiset<int> freed(workers.end() - mid, workers.end());
bool can = true;
for(int i = mid - 1; i >= 0 && can && used <= pills; --i) {
auto it = prev(freed.end());
if(*it < tasks[i]) {
it = freed.lower_bound(tasks[i] - strength);
if(it == freed.end()) {
can = false;
}
used += 1;
}
if(can && used <= pills) freed.erase(it);
}
if(can && used <= pills) {
low = mid;
} else {
high = mid - 1;
}
}
return low;
}
};
// Accepted
// 49/49 cases passed (661 ms)
// Your runtime beats 66.67 % of cpp submissions
// Your memory usage beats 83.33 % of cpp submissions (285.8 MB)