2025-03-10 Daily Challenge
Today I have done leetcode's March LeetCoding Challenge with cpp.
March LeetCoding Challenge 10
Description
Count of Substrings Containing Every Vowel and K Consonants II
You are given a string word and a non-negative integer k.
Return the total number of substrings of word that contain every vowel ('a', 'e', 'i', 'o', and 'u') at least once and exactly k consonants.
Example 1:
Input: word = "aeioqq", k = 1
Output: 0
Explanation:
There is no substring with every vowel.
Example 2:
Input: word = "aeiou", k = 0
Output: 1
Explanation:
The only substring with every vowel and zero consonants is word[0..4], which is "aeiou".
Example 3:
Input: word = "ieaouqqieaouqq", k = 1
Output: 3
Explanation:
The substrings with every vowel and one consonant are:
word[0..5], which is"ieaouq".word[6..11], which is"qieaou".word[7..12], which is"ieaouq".
Constraints:
5 <= word.length <= 2 * 105wordconsists only of lowercase English letters.0 <= k <= word.length - 5
Solution
inline bool isVowel(char c) {
return c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u';
}
class Solution {
long long geK(string word, int k) {
long long result = 0;
int start = 0;
unordered_map<char, int> vowelCount;
int consonants = 0;
for(int end = 0; end < word.length(); ++end) {
char c = word[end];
if(isVowel(c)) {
vowelCount[c] += 1;
} else {
consonants += 1;
}
while(vowelCount.size() == 5 && consonants >= k) {
result += word.length() - end;
char cs = word[start];
if(isVowel(cs)) {
vowelCount[cs] -= 1;
if(!vowelCount[cs]) vowelCount.erase(cs);
} else {
consonants -= 1;
}
start += 1;
}
}
return result;
}
public:
long long countOfSubstrings(string word, int k) {
return geK(word, k) - geK(word, k + 1);
}
};
// Accepted
// 768/768 cases passed (196 ms)
// Your runtime beats 51.12 % of cpp submissions
// Your memory usage beats 55.62 % of cpp submissions (48.7 MB)