2025-02-21 Daily Challenge
Today I have done leetcode's February LeetCoding Challenge with cpp
.
February LeetCoding Challenge 21
Description
Find Elements in a Contaminated Binary Tree
Given a binary tree with the following rules:
root.val == 0
- For any
treeNode
:- If
treeNode.val
has a valuex
andtreeNode.left != null
, thentreeNode.left.val == 2 * x + 1
- If
treeNode.val
has a valuex
andtreeNode.right != null
, thentreeNode.right.val == 2 * x + 2
- If
Now the binary tree is contaminated, which means all treeNode.val
have been changed to -1
.
Implement the FindElements
class:
FindElements(TreeNode* root)
Initializes the object with a contaminated binary tree and recovers it.bool find(int target)
Returnstrue
if thetarget
value exists in the recovered binary tree.
Example 1:

Input ["FindElements","find","find"] [[[-1,null,-1]],[1],[2]] Output [null,false,true] Explanation FindElements findElements = new FindElements([-1,null,-1]); findElements.find(1); // return False findElements.find(2); // return True
Example 2:

Input ["FindElements","find","find","find"] [[[-1,-1,-1,-1,-1]],[1],[3],[5]] Output [null,true,true,false] Explanation FindElements findElements = new FindElements([-1,-1,-1,-1,-1]); findElements.find(1); // return True findElements.find(3); // return True findElements.find(5); // return False
Example 3:

Input ["FindElements","find","find","find","find"] [[[-1,null,-1,-1,null,-1]],[2],[3],[4],[5]] Output [null,true,false,false,true] Explanation FindElements findElements = new FindElements([-1,null,-1,-1,null,-1]); findElements.find(2); // return True findElements.find(3); // return False findElements.find(4); // return False findElements.find(5); // return True
Constraints:
TreeNode.val == -1
- The height of the binary tree is less than or equal to
20
- The total number of nodes is between
[1, 104]
- Total calls of
find()
is between[1, 104]
0 <= target <= 106
Solution
class FindElements {
set<int> nodes;
void solve(TreeNode *root, int val) {
if(!root) return;
root->val = val;
nodes.insert(val);
solve(root->left, 2 * val + 1);
solve(root->right, 2 * val + 2);
}
public:
FindElements(TreeNode* root) {
solve(root, 0);
}
bool find(int target) {
return nodes.count(target);
}
};
// Accepted
// 31/31 cases passed (7 ms)
// Your runtime beats 82.43 % of cpp submissions
// Your memory usage beats 21.87 % of cpp submissions (34.9 MB)