2024-08-26 Daily Challenge
Today I have done leetcode's August LeetCoding Challenge with cpp
.
August LeetCoding Challenge 26
Description
N-ary Tree Postorder Traversal
Given the root
of an n-ary tree, return the postorder traversal of its nodes' values.
Nary-Tree input serialization is represented in their level order traversal. Each group of children is separated by the null value (See examples)
Example 1:
Input: root = [1,null,3,2,4,null,5,6] Output: [5,6,3,2,4,1]
Example 2:
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: [2,6,14,11,7,3,12,8,4,13,9,10,5,1]
Constraints:
- The number of nodes in the tree is in the range
[0, 104]
. 0 <= Node.val <= 104
- The height of the n-ary tree is less than or equal to
1000
.
Follow up: Recursive solution is trivial, could you do it iteratively?
Solution
class Solution {
void visit(vector<int> &answer, Node* root) {
for(auto child : root->children) {
visit(answer, child);
}
answer.push_back(root->val);
}
public:
vector<int> postorder(Node* root) {
if(!root) return {};
vector<int> answer;
visit(answer, root);
return answer;
}
};