2024-07-07 Daily Challenge

Today I have done leetcode's July LeetCoding Challenge with cpp.

July LeetCoding Challenge 7

Description

Water Bottles

There are numBottles water bottles that are initially full of water. You can exchange numExchange empty water bottles from the market with one full water bottle.

The operation of drinking a full water bottle turns it into an empty bottle.

Given the two integers numBottles and numExchange, return the maximum number of water bottles you can drink.

 

Example 1:

Input: numBottles = 9, numExchange = 3
Output: 13
Explanation: You can exchange 3 empty bottles to get 1 full water bottle.
Number of water bottles you can drink: 9 + 3 + 1 = 13.

Example 2:

Input: numBottles = 15, numExchange = 4
Output: 19
Explanation: You can exchange 4 empty bottles to get 1 full water bottle. 
Number of water bottles you can drink: 15 + 3 + 1 = 19.

 

Constraints:

  • 1 <= numBottles <= 100
  • 2 <= numExchange <= 100

Solution

class Solution {
public:
  int numWaterBottles(int numBottles, int numExchange) {
    int bottle = 0;
    int drink = 0;
    while(numBottles) {
      drink += numBottles;
      bottle = bottle + numBottles;
      numBottles = bottle / numExchange;
      bottle = bottle % numExchange;
    }
    return drink;
  }
};