2024-05-19 Daily Challenge
Today I have done leetcode's May LeetCoding Challenge with cpp
.
May LeetCoding Challenge 19
Description
Find the Maximum Sum of Node Values
There exists an undirected tree with n
nodes numbered 0
to n - 1
. You are given a 0-indexed 2D integer array edges
of length n - 1
, where edges[i] = [ui, vi]
indicates that there is an edge between nodes ui
and vi
in the tree. You are also given a positive integer k
, and a 0-indexed array of non-negative integers nums
of length n
, where nums[i]
represents the value of the node numbered i
.
Alice wants the sum of values of tree nodes to be maximum, for which Alice can perform the following operation any number of times (including zero) on the tree:
- Choose any edge
[u, v]
connecting the nodesu
andv
, and update their values as follows:<ul> <li><code>nums[u] = nums[u] XOR k</code></li> <li><code>nums[v] = nums[v] XOR k</code></li> </ul> </li>
Return the maximum possible sum of the values Alice can achieve by performing the operation any number of times.
Example 1:
Input: nums = [1,2,1], k = 3, edges = [[0,1],[0,2]] Output: 6 Explanation: Alice can achieve the maximum sum of 6 using a single operation: - Choose the edge [0,2]. nums[0] and nums[2] become: 1 XOR 3 = 2, and the array nums becomes: [1,2,1] -> [2,2,2]. The total sum of values is 2 + 2 + 2 = 6. It can be shown that 6 is the maximum achievable sum of values.
Example 2:
Input: nums = [2,3], k = 7, edges = [[0,1]] Output: 9 Explanation: Alice can achieve the maximum sum of 9 using a single operation: - Choose the edge [0,1]. nums[0] becomes: 2 XOR 7 = 5 and nums[1] become: 3 XOR 7 = 4, and the array nums becomes: [2,3] -> [5,4]. The total sum of values is 5 + 4 = 9. It can be shown that 9 is the maximum achievable sum of values.
Example 3:
Input: nums = [7,7,7,7,7,7], k = 3, edges = [[0,1],[0,2],[0,3],[0,4],[0,5]] Output: 42 Explanation: The maximum achievable sum is 42 which can be achieved by Alice performing no operations.
Constraints:
2 <= n == nums.length <= 2 * 104
1 <= k <= 109
0 <= nums[i] <= 109
edges.length == n - 1
edges[i].length == 2
0 <= edges[i][0], edges[i][1] <= n - 1
- The input is generated such that
edges
represent a valid tree.
Solution
class Solution {
public:
long long maximumValueSum(vector<int>& nums, int k, vector<vector<int>>& edges) {
long long total = accumulate(nums.begin(), nums.end(), 0ll);
long long total_diff = 0;
long long diff =-1;
int positive_count = 0;
long long min_abs_diff = numeric_limits<int>::max();
for(auto p : nums) {
diff = (p^k) - p;
if(diff > 0) {
total_diff += diff;
positive_count += 1;
}
min_abs_diff = min(min_abs_diff, abs(diff));
}
if(positive_count % 2) {
total_diff -= min_abs_diff;
}
return total + total_diff;
}
};