2024-01-25 Daily Challenge
Today I have done leetcode's January LeetCoding Challenge with cpp
.
January LeetCoding Challenge 25
Description
Longest Common Subsequence
Given two strings text1
and text2
, return the length of their longest common subsequence. If there is no common subsequence, return 0
.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
- For example,
"ace"
is a subsequence of"abcde"
.
A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = "abcde", text2 = "ace" Output: 3 Explanation: The longest common subsequence is "ace" and its length is 3.
Example 2:
Input: text1 = "abc", text2 = "abc" Output: 3 Explanation: The longest common subsequence is "abc" and its length is 3.
Example 3:
Input: text1 = "abc", text2 = "def" Output: 0 Explanation: There is no such common subsequence, so the result is 0.
Constraints:
1 <= text1.length, text2.length <= 1000
text1
andtext2
consist of only lowercase English characters.
Solution
auto speedup = [](){
cin.tie(nullptr);
cout.tie(nullptr);
ios::sync_with_stdio(false);
return 0;
}();
class Solution {
int dp[2][1001] = {};
public:
int longestCommonSubsequence(string text1, string text2) {
int len1 = text1.length();
int len2 = text2.length();
for(int i = 0; i < len1; ++i) {
int parity = i & 1;
for(int j = 0; j < len2; ++j) {
dp[parity][j + 1] = max({dp[!parity][j + 1], dp[parity][j], dp[!parity][j] + (text1[i] == text2[j])});
}
}
return dp[~len1 & 1][len2];
}
};
// Accepted
// 47/47 cases passed (20 ms)
// Your runtime beats 90.94 % of cpp submissions
// Your memory usage beats 87.25 % of cpp submissions (8.3 MB)