2023-11-29 Daily Challenge
Today I have done leetcode's November LeetCoding Challenge with cpp
.
November LeetCoding Challenge 29
Description
Number of 1 Bits
Write a function that takes the binary representation of an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight).
Note:
- Note that in some languages, such as Java, there is no unsigned integer type. In this case, the input will be given as a signed integer type. It should not affect your implementation, as the integer's internal binary representation is the same, whether it is signed or unsigned.
- In Java, the compiler represents the signed integers using 2's complement notation. Therefore, in Example 3, the input represents the signed integer.
-3
.
Example 1:
Input: n = 00000000000000000000000000001011 Output: 3 Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.
Example 2:
Input: n = 00000000000000000000000010000000 Output: 1 Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.
Example 3:
Input: n = 11111111111111111111111111111101 Output: 31 Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.
Constraints:
- The input must be a binary string of length
32
.
Follow up: If this function is called many times, how would you optimize it?
Solution
const uint32_t m1 = 0x55555555;
const uint32_t m2 = 0x33333333;
const uint32_t m4 = 0x0F0F0F0F;
const uint32_t m8 = 0x00FF00FF;
const uint32_t m16 = 0x0000FFFF;
class Solution {
public:
int hammingWeight(uint32_t n) {
n = (n & m1) + ((n >> 1) & m1);
n = (n & m2) + ((n >> 2) & m2);
n = (n & m4) + ((n >> 4) & m4);
n = (n & m8) + ((n >> 8) & m8);
n = (n & m16) + ((n >> 16) & m16);
return n;
}
};
// Accepted
// 601/601 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 57.22 % of cpp submissions (6.4 MB)