2023-11-23 Daily Challenge

Today I have done leetcode's November LeetCoding Challenge with cpp.

November LeetCoding Challenge 23

Description

Arithmetic Subarrays

A sequence of numbers is called arithmetic if it consists of at least two elements, and the difference between every two consecutive elements is the same. More formally, a sequence s is arithmetic if and only if s[i+1] - s[i] == s[1] - s[0] for all valid i.

For example, these are arithmetic sequences:

1, 3, 5, 7, 9
7, 7, 7, 7
3, -1, -5, -9

The following sequence is not arithmetic:

1, 1, 2, 5, 7

You are given an array of n integers, nums, and two arrays of m integers each, l and r, representing the m range queries, where the ith query is the range [l[i], r[i]]. All the arrays are 0-indexed.

Return a list of boolean elements answer, where answer[i] is true if the subarray nums[l[i]], nums[l[i]+1], ... , nums[r[i]] can be rearranged to form an arithmetic sequence, and false otherwise.

 

Example 1:

Input: nums = [4,6,5,9,3,7], l = [0,0,2], r = [2,3,5]
Output: [true,false,true]
Explanation:
In the 0th query, the subarray is [4,6,5]. This can be rearranged as [6,5,4], which is an arithmetic sequence.
In the 1st query, the subarray is [4,6,5,9]. This cannot be rearranged as an arithmetic sequence.
In the 2nd query, the subarray is [5,9,3,7]. This can be rearranged as [3,5,7,9], which is an arithmetic sequence.

Example 2:

Input: nums = [-12,-9,-3,-12,-6,15,20,-25,-20,-15,-10], l = [0,1,6,4,8,7], r = [4,4,9,7,9,10]
Output: [false,true,false,false,true,true]

 

Constraints:

  • n == nums.length
  • m == l.length
  • m == r.length
  • 2 <= n <= 500
  • 1 <= m <= 500
  • 0 <= l[i] < r[i] < n
  • -105 <= nums[i] <= 105

Solution

class Solution {
  bool check(vector<int> v) {
    sort(v.begin(), v.end());
    int diff = v[1] - v[0];
    for(int i = 2; i < v.size(); ++i) {
      if(v[i] - v[i - 1] != diff) return false;
    }
    return true;
  }
public:
  vector<bool> checkArithmeticSubarrays(vector<int>& nums, vector<int>& l, vector<int>& r) {
    vector<bool> answer;
    for(int i = 0 ; i < l.size(); ++i) {
      vector<int> newV(nums.begin() + l[i], nums.begin() + r[i] + 1);
      answer.push_back(check(newV));
    }
    return answer;
  }
};

// Accepted
// 102/102 cases passed (49 ms)
// Your runtime beats 68.67 % of cpp submissions
// Your memory usage beats 59.9 % of cpp submissions (31.1 MB)