Today I have done leetcode's November LeetCoding Challenge with cpp.

November LeetCoding Challenge 5

Description

Find the Winner of an Array Game

Given an integer array arr of distinct integers and an integer k.

A game will be played between the first two elements of the array (i.e. arr[0] and arr[1]). In each round of the game, we compare arr[0] with arr[1], the larger integer wins and remains at position 0, and the smaller integer moves to the end of the array. The game ends when an integer wins k consecutive rounds.

Return the integer which will win the game.

It is guaranteed that there will be a winner of the game.

Example 1:

Input: arr = [2,1,3,5,4,6,7], k = 2
Output: 5
Explanation: Let's see the rounds of the game:
Round |       arr       | winner | win_count
  1   | [2,1,3,5,4,6,7] | 2      | 1
  2   | [2,3,5,4,6,7,1] | 3      | 1
  3   | [3,5,4,6,7,1,2] | 5      | 1
  4   | [5,4,6,7,1,2,3] | 5      | 2
So we can see that 4 rounds will be played and 5 is the winner because it wins 2 consecutive games.

Example 2:

Input: arr = [3,2,1], k = 10
Output: 3
Explanation: 3 will win the first 10 rounds consecutively.

Constraints:

• 2 <= arr.length <= 105
• 1 <= arr[i] <= 106
• arr contains distinct integers.
• 1 <= k <= 109

Solution

class Solution {
public:
  int getWinner(vector<int>& arr, int k) {
    int answer = 0;
    int count = 0;
    int candidate = arr.front();
    for(int i = 1; i < arr.size(); ++i) {
      if(candidate <= arr[i]) {
        candidate = arr[i];
        count = 0;
      }
      count += 1;
      if(count == k) {
        return candidate;
      }
    }
    return candidate;
  }
};

// Accepted
// 185/185 cases passed (64 ms)
// Your runtime beats 98.61 % of cpp submissions
// Your memory usage beats 40.28 % of cpp submissions (63.5 MB)