2023-05-17 Daily Challenge
Today I have done leetcode's May LeetCoding Challenge with cpp
.
May LeetCoding Challenge 17
Description
Maximum Twin Sum of a Linked List
In a linked list of size n
, where n
is even, the ith
node (0-indexed) of the linked list is known as the twin of the (n-1-i)th
node, if 0 <= i <= (n / 2) - 1
.
- For example, if
n = 4
, then node0
is the twin of node3
, and node1
is the twin of node2
. These are the only nodes with twins forn = 4
.
The twin sum is defined as the sum of a node and its twin.
Given the head
of a linked list with even length, return the maximum twin sum of the linked list.
Example 1:
Input: head = [5,4,2,1] Output: 6 Explanation: Nodes 0 and 1 are the twins of nodes 3 and 2, respectively. All have twin sum = 6. There are no other nodes with twins in the linked list. Thus, the maximum twin sum of the linked list is 6.
Example 2:
Input: head = [4,2,2,3] Output: 7 Explanation: The nodes with twins present in this linked list are: - Node 0 is the twin of node 3 having a twin sum of 4 + 3 = 7. - Node 1 is the twin of node 2 having a twin sum of 2 + 2 = 4. Thus, the maximum twin sum of the linked list is max(7, 4) = 7.
Example 3:
Input: head = [1,100000] Output: 100001 Explanation: There is only one node with a twin in the linked list having twin sum of 1 + 100000 = 100001.
Constraints:
- The number of nodes in the list is an even integer in the range
[2, 105]
. 1 <= Node.val <= 105
Solution
auto speedup = [](){
cin.tie(nullptr);
cout.tie(nullptr);
ios::sync_with_stdio(false);
return 0;
}();
class Solution {
public:
int pairSum(ListNode* head) {
vector<int> nums;
while(head) {
nums.push_back(head->val);
head = head->next;
}
int answer = 0;
int len = nums.size();
for(int i = 0; i < len / 2; ++i) {
answer = max(answer, nums[i] + nums[len - i - 1]);
}
return answer;
}
};
// Accepted
// 46/46 cases passed (200 ms)
// Your runtime beats 99.58 % of cpp submissions
// Your memory usage beats 42.56 % of cpp submissions (126.5 MB)