2023-02-02 Daily Challenge
Today I have done leetcode's February LeetCoding Challenge with cpp
.
February LeetCoding Challenge 2
Description
Verifying an Alien Dictionary
In an alien language, surprisingly, they also use English lowercase letters, but possibly in a different order
. The order
of the alphabet is some permutation of lowercase letters.
Given a sequence of words
written in the alien language, and the order
of the alphabet, return true
if and only if the given words
are sorted lexicographically in this alien language.
Example 1:
Input: words = ["hello","leetcode"], order = "hlabcdefgijkmnopqrstuvwxyz" Output: true Explanation: As 'h' comes before 'l' in this language, then the sequence is sorted.
Example 2:
Input: words = ["word","world","row"], order = "worldabcefghijkmnpqstuvxyz" Output: false Explanation: As 'd' comes after 'l' in this language, then words[0] > words[1], hence the sequence is unsorted.
Example 3:
Input: words = ["apple","app"], order = "abcdefghijklmnopqrstuvwxyz" Output: false Explanation: The first three characters "app" match, and the second string is shorter (in size.) According to lexicographical rules "apple" > "app", because 'l' > '∅', where '∅' is defined as the blank character which is less than any other character (More info).
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 20
order.length == 26
- All characters in
words[i]
andorder
are English lowercase letters.
Solution
class Solution {
public:
bool isAlienSorted(vector<string>& words, string order) {
int orderIndex[128] = {};
int pos = 0;
for(auto c : order) orderIndex[c] = pos++;
return is_sorted(words.begin(), words.end(), [&](const string &a, const string &b) {
for(int i = 0; i < min(a.length(), b.length()); ++i) {
if(a[i] != b[i]) return orderIndex[a[i]] < orderIndex[b[i]];
}
return a.length() < b.length();
});
}
};
// Accepted
// 120/120 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 99.14 % of cpp submissions (9.2 MB)