2022-10-10 Daily-Challenge
Today I have done leetcode's October LeetCoding Challenge with cpp
.
October LeetCoding Challenge 10
Description
Break a Palindrome
Given a palindromic string of lowercase English letters palindrome
, replace exactly one character with any lowercase English letter so that the resulting string is not a palindrome and that it is the lexicographically smallest one possible.
Return the resulting string. If there is no way to replace a character to make it not a palindrome, return an empty string.
A string a
is lexicographically smaller than a string b
(of the same length) if in the first position where a
and b
differ, a
has a character strictly smaller than the corresponding character in b
. For example, "abcc"
is lexicographically smaller than "abcd"
because the first position they differ is at the fourth character, and 'c'
is smaller than 'd'
.
Example 1:
Input: palindrome = "abccba"
Output: "aaccba"
Explanation: There are many ways to make "abccba" not a palindrome, such as "zbccba", "aaccba", and "abacba".
Of all the ways, "aaccba" is the lexicographically smallest.
Example 2:
Input: palindrome = "a"
Output: ""
Explanation: There is no way to replace a single character to make "a" not a palindrome, so return an empty string.
Constraints:
1 <= palindrome.length <= 1000
palindrome
consists of only lowercase English letters.
Solution
class Solution {
public:
string breakPalindrome(string palindrome) {
int len = palindrome.length();
if(len == 1) return "";
for(int i = 0; i * 2 + 1 < len; ++i) {
if(palindrome[i] != 'a') {
palindrome[i] = 'a';
return palindrome;
}
}
palindrome.back() = 'b';
return palindrome;
}
};
// Accepted
// 30/30 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 45.58 % of cpp submissions (6.2 MB)