2022-08-10 Daily-Challenge
Today I have done leetcode's August LeetCoding Challenge with cpp
.
August LeetCoding Challenge 10
Description
Convert Sorted Array to Binary Search Tree
Given an integer array nums
where the elements are sorted in ascending order, convert it to a height-balanced binary search tree.
A height-balanced binary tree is a binary tree in which the depth of the two subtrees of every node never differs by more than one.
Example 1:
Input: nums = [-10,-3,0,5,9]
Output: [0,-3,9,-10,null,5]
Explanation: [0,-10,5,null,-3,null,9] is also accepted:
Example 2:
Input: nums = [1,3]
Output: [3,1]
Explanation: [1,null,3] and [3,1] are both height-balanced BSTs.
Constraints:
1 <= nums.length <= 10^4
-10^4 <= nums[i] <= 10^4
nums
is sorted in a strictly increasing order.
Solution
class Solution {
TreeNode *construct(vector<int> &nums, int begin, int end) {
if(begin > end) return nullptr;
int mid = (begin + end) >> 1;
TreeNode *root = new TreeNode(nums[mid]);
root->left = construct(nums, begin, mid - 1);
root->right = construct(nums, mid + 1, end);
return root;
}
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
int len = nums.size();
return construct(nums, 0, len - 1);
}
};
// Accepted
// 31/31 cases passed (8 ms)
// Your runtime beats 95.55 % of cpp submissions
// Your memory usage beats 75.67 % of cpp submissions (21.4 MB)