2022-08-03 Daily-Challenge

Today I have done leetcode's August LeetCoding Challenge with cpp.

August LeetCoding Challenge 3

Description

My Calendar I

You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a double booking.

A double booking happens when two events have some non-empty intersection (i.e., some moment is common to both events.).

The event can be represented as a pair of integers start and end that represents a booking on the half-open interval [start, end), the range of real numbers x such that start <= x < end.

Implement the MyCalendar class:

  • MyCalendar() Initializes the calendar object.
  • boolean book(int start, int end) Returns true if the event can be added to the calendar successfully without causing a double booking. Otherwise, return false and do not add the event to the calendar.

Example 1:

Input
["MyCalendar", "book", "book", "book"]
[[], [10, 20], [15, 25], [20, 30]]
Output
[null, true, false, true]

Explanation
MyCalendar myCalendar = new MyCalendar();
myCalendar.book(10, 20); // return True
myCalendar.book(15, 25); // return False, It can not be booked because time 15 is already booked by another event.
myCalendar.book(20, 30); // return True, The event can be booked, as the first event takes every time less than 20, but not including 20.

Constraints:

  • 0 <= start < end <= 10&9
  • At most 1000 calls will be made to book.

Solution

class MyCalendar {
  set<pair<int, int>> times;
public:
  MyCalendar(){}
  
  bool book(int start, int end) {
    auto it = times.upper_bound({start, end});
    if(it != times.end() && it->second < end) return false;
    times.insert({end, start});
    return true;
  }
};

// Accepted
// 107/107 cases passed (167 ms)
// Your runtime beats 51.09 % of cpp submissions
// Your memory usage beats 31.77 % of cpp submissions (38.9 MB)