2022-08-03 Daily-Challenge
Today I have done leetcode's August LeetCoding Challenge with cpp
.
August LeetCoding Challenge 3
Description
My Calendar I
You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a double booking.
A double booking happens when two events have some non-empty intersection (i.e., some moment is common to both events.).
The event can be represented as a pair of integers start
and end
that represents a booking on the half-open interval [start, end)
, the range of real numbers x
such that start <= x < end
.
Implement the MyCalendar
class:
MyCalendar()
Initializes the calendar object.boolean book(int start, int end)
Returnstrue
if the event can be added to the calendar successfully without causing a double booking. Otherwise, returnfalse
and do not add the event to the calendar.
Example 1:
Input
["MyCalendar", "book", "book", "book"]
[[], [10, 20], [15, 25], [20, 30]]
Output
[null, true, false, true]
Explanation
MyCalendar myCalendar = new MyCalendar();
myCalendar.book(10, 20); // return True
myCalendar.book(15, 25); // return False, It can not be booked because time 15 is already booked by another event.
myCalendar.book(20, 30); // return True, The event can be booked, as the first event takes every time less than 20, but not including 20.
Constraints:
0 <= start < end <= 10&9
- At most
1000
calls will be made tobook
.
Solution
class MyCalendar {
set<pair<int, int>> times;
public:
MyCalendar(){}
bool book(int start, int end) {
auto it = times.upper_bound({start, end});
if(it != times.end() && it->second < end) return false;
times.insert({end, start});
return true;
}
};
// Accepted
// 107/107 cases passed (167 ms)
// Your runtime beats 51.09 % of cpp submissions
// Your memory usage beats 31.77 % of cpp submissions (38.9 MB)