2022-07-04 Daily-Challenge
Today I have done leetcode's July LeetCoding Challenge with cpp
.
July LeetCoding Challenge 4
Description
Candy
There are n
children standing in a line. Each child is assigned a rating value given in the integer array ratings
.
You are giving candies to these children subjected to the following requirements:
- Each child must have at least one candy.
- Children with a higher rating get more candies than their neighbors.
Return the minimum number of candies you need to have to distribute the candies to the children.
Example 1:
Input: ratings = [1,0,2]
Output: 5
Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively.
Example 2:
Input: ratings = [1,2,2]
Output: 4
Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively.
The third child gets 1 candy because it satisfies the above two conditions.
Constraints:
n == ratings.length
1 <= n <= 2 * 10^4
0 <= ratings[i] <= 2 * 10^4
Solution
using pi = pair<int, int>;
int cd[20000];
class Solution {
public:
int candy(vector<int>& ratings) {
priority_queue<pi, vector<pi>, greater<pi>> pq;
int len = ratings.size();
for(int i = 0; i < len; ++i) {
pq.push({ratings[i], i});
cd[i] = 0;
}
while(pq.size()) {
auto [rating, pos] = pq.top();
pq.pop();
if(cd[pos]) continue;
cd[pos] = 1;
for(int i = pos + 1; i < len; ++i) {
if(ratings[i] <= ratings[i - 1]) break;
if(cd[i] > cd[i - 1] + 1) break;
cd[i] = cd[i - 1] + 1;
}
for(int i = pos - 1; i >= 0; --i) {
if(ratings[i] <= ratings[i + 1]) break;
if(cd[i] > cd[i + 1] + 1) break;
cd[i] = cd[i + 1] + 1;
}
}
int answer = 0;
for(int i = 0; i < len; ++i) {
// cout << cd[i] << ' ';
answer += cd[i];
}
// cout << endl;
return answer;
}
};
// Accepted
// 48/48 cases passed (56 ms)
// Your runtime beats 12.87 % of cpp submissions
// Your memory usage beats 8.43 % of cpp submissions (19.8 MB)