2022-01-28 Daily-Challenge
Today I have done leetcode's January LeetCoding Challenge with cpp
.
January LeetCoding Challenge 28
Description
Design Add and Search Words Data Structure
Design a data structure that supports adding new words and finding if a string matches any previously added string.
Implement the WordDictionary
class:
WordDictionary()
Initializes the object.void addWord(word)
Addsword
to the data structure, it can be matched later.bool search(word)
Returnstrue
if there is any string in the data structure that matchesword
orfalse
otherwise.word
may contain dots'.'
where dots can be matched with any letter.
Example:
Input
["WordDictionary","addWord","addWord","addWord","search","search","search","search"]
[[],["bad"],["dad"],["mad"],["pad"],["bad"],[".ad"],["b.."]]
Output
[null,null,null,null,false,true,true,true]
Explanation
WordDictionary wordDictionary = new WordDictionary();
wordDictionary.addWord("bad");
wordDictionary.addWord("dad");
wordDictionary.addWord("mad");
wordDictionary.search("pad"); // return False
wordDictionary.search("bad"); // return True
wordDictionary.search(".ad"); // return True
wordDictionary.search("b.."); // return True
Constraints:
1 <= word.length <= 500
word
inaddWord
consists lower-case English letters.word
insearch
consist of'.'
or lower-case English letters.- At most
50000
calls will be made toaddWord
andsearch
.
Solution
auto speedup = [](){
cin.tie(nullptr);
cout.tie(nullptr);
ios::sync_with_stdio(false);
return 0;
}();
struct TrieNode {
bool end = false;
TrieNode *children[26] = {};
~TrieNode() {
for(auto child : children) delete child;
}
};
class WordDictionary {
TrieNode *root;
bool helper(const string &word, TrieNode *cur, int pos = 0) {
int len = word.length();
for(int i = pos; i < len; ++i) {
if(word[i] != '.') {
if(!cur->children[word[i] - 'a']) return false;
cur = cur->children[word[i] - 'a'];
} else {
for(auto child : cur->children) {
if(child && helper(word, child, i + 1)) return true;
}
return false;
}
}
return cur->end;
}
public:
WordDictionary() {
root = new TrieNode();
}
~WordDictionary() {
delete root;
}
void addWord(string word) {
TrieNode *cur = root;
for(auto c : word) {
c -= 'a';
if(!cur->children[c]) {
cur->children[c] = new TrieNode();
}
cur = cur->children[c];
}
cur->end = true;
}
bool search(string word) {
return helper(word, root);
}
};
// Accepted
// 13/13 cases passed (84 ms)
// Your runtime beats 75.72 % of cpp submissions
// Your memory usage beats 57.03 % of cpp submissions (43.7 MB)