2022-01-23 Daily-Challenge
Today I have done leetcode's January LeetCoding Challenge with cpp
.
January LeetCoding Challenge 23
Description
Sequential Digits
An integer has sequential digits if and only if each digit in the number is one more than the previous digit.
Return a sorted list of all the integers in the range [low, high]
inclusive that have sequential digits.
Example 1:
Input: low = 100, high = 300
Output: [123,234]
Example 2:
Input: low = 1000, high = 13000
Output: [1234,2345,3456,4567,5678,6789,12345]
Constraints:
10 <= low <= high <= 10^9
Solution
const vector<int> nums{1, 12, 123, 1234, 12345, 123456, 1234567, 12345678, 123456789};
class Solution {
public:
vector<int> sequentialDigits(int low, int high) {
int diff = 0;
vector<int> answer;
for(auto num : nums) {
diff = diff * 10 + 1;
if(num > high) break;
while(num % 10 && num <= high) {
if(num >= low) answer.push_back(num);
num += diff;
}
}
return answer;
}
};
// Accepted
// 23/23 cases passed (3 ms)
// Your runtime beats 18.21 % of cpp submissions
// Your memory usage beats 76.43 % of cpp submissions (6.2 MB)