2022-01-16 Daily-Challenge
Today I have done leetcode's January LeetCoding Challenge with cpp
.
January LeetCoding Challenge 16
Description
Maximize Distance to Closest Person
You are given an array representing a row of seats
where seats[i] = 1
represents a person sitting in the ith
seat, and seats[i] = 0
represents that the ith
seat is empty (0-indexed).
There is at least one empty seat, and at least one person sitting.
Alex wants to sit in the seat such that the distance between him and the closest person to him is maximized.
Return that maximum distance to the closest person.
Example 1:
Input: seats = [1,0,0,0,1,0,1]
Output: 2
Explanation:
If Alex sits in the second open seat (i.e. seats[2]), then the closest person has distance 2.
If Alex sits in any other open seat, the closest person has distance 1.
Thus, the maximum distance to the closest person is 2.
Example 2:
Input: seats = [1,0,0,0]
Output: 3
Explanation:
If Alex sits in the last seat (i.e. seats[3]), the closest person is 3 seats away.
This is the maximum distance possible, so the answer is 3.
Example 3:
Input: seats = [0,1]
Output: 1
Constraints:
2 <= seats.length <= 2 * 10^4
seats[i]
is0
or1
.- At least one seat is empty.
- At least one seat is occupied.
Solution
class Solution {
public:
int maxDistToClosest(vector<int>& seats) {
bool begin = true;
int count = 0;
int answer = 0;
for(auto seat : seats) {
if(!seat) {
count += 1;
continue;
}
if(begin) {
count *= 2;
begin = false;
}
answer = max(answer, count / 2);
count = 1;
}
if(count > 1) answer = max(answer, count - 1);
return answer;
}
};
// Accepted
// 81/81 cases passed (8 ms)
// Your runtime beats 96.68 % of cpp submissions
// Your memory usage beats 63.67 % of cpp submissions (17 MB)