2022-01-12 Daily-Challenge

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In: DailyChallenge

Today I have done leetcode's January LeetCoding Challenge with cpp.

January LeetCoding Challenge 12

Description

Insert into a Binary Search Tree

You are given the root node of a binary search tree (BST) and a value to insert into the tree. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST.

Notice that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return any of them.

Example 1:

img

Input: root = [4,2,7,1,3], val = 5
Output: [4,2,7,1,3,5]
Explanation: Another accepted tree is:

Example 2:

Input: root = [40,20,60,10,30,50,70], val = 25
Output: [40,20,60,10,30,50,70,null,null,25]

Example 3:

Input: root = [4,2,7,1,3,null,null,null,null,null,null], val = 5
Output: [4,2,7,1,3,5]

Constraints:

  • The number of nodes in the tree will be in the range [0, 104].
  • -108 <= Node.val <= 108
  • All the values Node.val are unique.
  • -108 <= val <= 108
  • It's guaranteed that val does not exist in the original BST.

Solution

auto speedup = [](){
  cin.tie(nullptr);
  cout.tie(nullptr);
  ios::sync_with_stdio(false);
  return 0;
}();
class Solution {
public:
  TreeNode* insertIntoBST(TreeNode* root, int val) {
    if(!root) return new TreeNode(val);
    if(root->val > val) {
      root->left = insertIntoBST(root->left, val);
    } else {
      root->right = insertIntoBST(root->right, val);
    }
    return root;
  }
};

// Accepted
// 35/35 cases passed (136 ms)
// Your runtime beats 21.66 % of cpp submissions
// Your memory usage beats 80.92 % of cpp submissions (56.9 MB)
Algorithm