Today I have done leetcode's November LeetCoding Challenge with cpp.

November LeetCoding Challenge 26

Description

Search Insert Position

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

Example 1:

Input: nums = [1,3,5,6], target = 5
Output: 2

Example 2:

Input: nums = [1,3,5,6], target = 2
Output: 1

Example 3:

Input: nums = [1,3,5,6], target = 7
Output: 4

Example 4:

Input: nums = [1,3,5,6], target = 0
Output: 0

Example 5:

Input: nums = [1], target = 0
Output: 0

Constraints:

• 1 <= nums.length <= 10^4
• -10^4 <= nums[i] <= 10^4
• nums contains distinct values sorted in ascending order.
• -10^4 <= target <= 10^4

Solution

auto speedup = [](){
  cin.tie(nullptr);
  cout.tie(nullptr);
  ios::sync_with_stdio(false);
  return 0;
}();
class Solution {
public:
  int searchInsert(vector<int>& nums, int target) {
    int begin = 0, end = nums.size();
    nums.push_back(INT_MAX);
    while(begin < end) {
      int mid = (begin + end) >> 1;
      if(nums[mid] < target) {
        begin = mid + 1;
      } else {
        end = mid;
      }
    }
    return begin;
  }
};

// Accepted
// 64/64 cases passed (3 ms)
// Your runtime beats 84.06 % of cpp submissions
// Your memory usage beats 72.14 % of cpp submissions (9.7 MB)