Today I have done leetcode's November LeetCoding Challenge with cpp.

November LeetCoding Challenge 11

Description

Minimum Value to Get Positive Step by Step Sum

Given an array of integers nums, you start with an initial positive value startValue*.*

In each iteration, you calculate the step by step sum of startValue plus elements in nums (from left to right).

Return the minimum positive value of startValue such that the step by step sum is never less than 1.

Example 1:

Input: nums = [-3,2,-3,4,2]
Output: 5
Explanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.
                step by step sum
                startValue = 4 | startValue = 5 | nums
                  (4 -3 ) = 1  | (5 -3 ) = 2    |  -3
                  (1 +2 ) = 3  | (2 +2 ) = 4    |   2
                  (3 -3 ) = 0  | (4 -3 ) = 1    |  -3
                  (0 +4 ) = 4  | (1 +4 ) = 5    |   4
                  (4 +2 ) = 6  | (5 +2 ) = 7    |   2

Example 2:

Input: nums = [1,2]
Output: 1
Explanation: Minimum start value should be positive. 

Example 3:

Input: nums = [1,-2,-3]
Output: 5

Constraints:

• 1 <= nums.length <= 100
• -100 <= nums[i] <= 100

Solution

class Solution {
public:
  int minStartValue(vector<int>& nums) {
    int answer = 1;
    int sumRev = 1;
    for(auto i : nums) {
      sumRev -= i;
      if(answer < sumRev) answer = sumRev;
    }
    return answer;
  }
};

// Accepted
// 53/53 cases passed (0 ms)
// Your runtime beats 100 % of cpp submissions
// Your memory usage beats 14.12 % of cpp submissions (7.4 MB)