2021-11-09 Daily-Challenge
Today I have done leetcode's November LeetCoding Challenge with cpp
.
November LeetCoding Challenge 9
Description
Number of Valid Words for Each Puzzle
With respect to a given puzzle
string, a word
is valid if both the following conditions are satisfied:
-
word
contains the first letter ofpuzzle
. -
For each letter in
word
, that letter is in
puzzle
.
- For example, if the puzzle is
"abcdefg"
, then valid words are"faced"
,"cabbage"
, and"baggage"
, while - invalid words are
"beefed"
(does not include'a'
) and"based"
(includes's'
which is not in the puzzle).
- For example, if the puzzle is
Return an array answer
, where answer[i]
is the number of words in the given word list words
that is valid with respect to the puzzle puzzles[i]
.
Example 1:
Input: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"]
Output: [1,1,3,2,4,0]
Explanation:
1 valid word for "aboveyz" : "aaaa"
1 valid word for "abrodyz" : "aaaa"
3 valid words for "abslute" : "aaaa", "asas", "able"
2 valid words for "absoryz" : "aaaa", "asas"
4 valid words for "actresz" : "aaaa", "asas", "actt", "access"
There are no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.
Example 2:
Input: words = ["apple","pleas","please"], puzzles = ["aelwxyz","aelpxyz","aelpsxy","saelpxy","xaelpsy"]
Output: [0,1,3,2,0]
Constraints:
1 <= words.length <= 10^5
4 <= words[i].length <= 50
1 <= puzzles.length <= 10^4
puzzles[i].length == 7
words[i]
andpuzzles[i]
consist of lowercase English letters.- Each
puzzles[i]
does not contain repeated characters.
Solution
class Solution {
int bitmask(const string &s) {
int mask = 0;
for(auto c : s) {
mask |= (1 << (c - 'a'));
}
return mask;
}
public:
vector<int> findNumOfValidWords(vector<string>& words, vector<string>& puzzles) {
unordered_map<int, int> count;
for(auto &word : words) {
sort(word.begin(), word.end());
word.resize(unique(word.begin(), word.end()) - word.begin());
count[bitmask(word)] += 1;
}
vector<int> answer;
answer.reserve(puzzles.size());
for(auto &puzzle : puzzles) {
int first = (1 << (puzzle.front() - 'a'));
int result = count[first];
int mask = bitmask(puzzle.substr(1));
for(int submask = mask; submask; submask = (submask - 1) & mask) {
result += count[submask | first];
}
answer.push_back(result);
}
return answer;
}
};
// Accepted
// 10/10 cases passed (176 ms)
// Your runtime beats 81.43 % of cpp submissions
// Your memory usage beats 61.43 % of cpp submissions (47.3 MB)
struct TrieNode {
int count = 0;
TrieNode *child[26] = {};
};
void insert(TrieNode *root, const string &word) {
TrieNode *cur = root;
for(auto c : word) {
c -= 'a';
if(!cur->child[c]) {
cur->child[c] = new TrieNode();
}
cur = cur->child[c];
}
cur->count += 1;
}
class Solution {
int dfs(TrieNode *root, bool hasFirst, const string &puzzle/*, int level */) {
int total = hasFirst ? root->count : 0;
// cout << puzzle << level << ' ' << total << endl;
for(auto c : puzzle) {
int i = c - 'a';
if(root->child[i]) {
total += dfs(root->child[i], hasFirst || c == puzzle.front(), puzzle/*, level + 1 */);
}
}
// cout << puzzle << level << ' ' << total << endl;
return total;
}
public:
vector<int> findNumOfValidWords(vector<string>& words, vector<string>& puzzles) {
TrieNode *root = new TrieNode();
for(auto &word : words) {
sort(word.begin(), word.end());
word.erase(unique(word.begin(), word.end()), word.end());
if(word.size() > 7) continue;
insert(root, word);
}
vector<int> answer;
answer.reserve(puzzles.size());
for(const auto &puzzle : puzzles) {
answer.push_back(dfs(root, false, puzzle/*, 0 */));
}
return answer;
}
};
// Accepted
// 10/10 cases passed (208 ms)
// Your runtime beats 70.95 % of cpp submissions
// Your memory usage beats 30.95 % of cpp submissions (73.4 MB)