2021-10-24 Daily-Challenge
Today I have done leetcode's October LeetCoding Challenge with cpp
.
October LeetCoding Challenge 24
Description
Count Complete Tree Nodes
Given the root
of a complete binary tree, return the number of the nodes in the tree.
According to Wikipedia, every level, except possibly the last, is completely filled in a complete binary tree, and all nodes in the last level are as far left as possible. It can have between 1
and 2h
nodes inclusive at the last level h
.
Design an algorithm that runs in less than O(n)
time complexity.
Example 1:
Input: root = [1,2,3,4,5,6]
Output: 6
Example 2:
Input: root = []
Output: 0
Example 3:
Input: root = [1]
Output: 1
Constraints:
- The number of nodes in the tree is in the range
[0, 5 * 10^4]
. 0 <= Node.val <= 5 * 10^4
- The tree is guaranteed to be complete.
Solution
auto speedup = [](){
cin.tie(nullptr);
cout.tie(nullptr);
ios::sync_with_stdio(false);
return 0;
}();
class Solution {
public:
int countNodes(TreeNode* root) {
if(!root) return 0;
TreeNode* left = root;
TreeNode* right = root;
int count = 0;
while(left && right) {
left = left->left;
right = right->right;
count += 1;
}
if(!left && !right) return (1 << count) - 1;
return 1 + countNodes(root->left) + countNodes(root->right);
}
};
// Accepted
// 18/18 cases passed (62 ms)
// Your runtime beats 13.83 % of cpp submissions
// Your memory usage beats 21.46 % of cpp submissions (30.9 MB)