Today I have done Next Greater Element I on leetcode and leetcode's November LeetCoding Challenge with cpp.

Next Greater Element I

Description

You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.

The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. If it does not exist, output -1 for this number.

Example 1:

Input: nums1 = [4,1,2], nums2 = [1,3,4,2].
Output: [-1,3,-1]
Explanation:
    For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1.
    For number 1 in the first array, the next greater number for it in the second array is 3.
    For number 2 in the first array, there is no next greater number for it in the second array, so output -1.

Example 2:

Input: nums1 = [2,4], nums2 = [1,2,3,4].
Output: [3,-1]
Explanation:
    For number 2 in the first array, the next greater number for it in the second array is 3.
    For number 4 in the first array, there is no next greater number for it in the second array, so output -1.

Note:

1. All elements in nums1 and nums2 are unique.
2. The length of both nums1 and nums2 would not exceed 1000.

Solution

monotonic stack

class Solution {
public:
    vector<int> nextGreaterElement(vector<int>& nums1, vector<int>& nums2) {
        map<int, int> pos;
        for(int i = 0; i < nums2.size(); ++i) {
            pos[nums2[i]] = i;
        }
        stack<int, vector<int>> monoStack;
        vector<int> nextGreaterElement(nums2.size());
        for(int i = nums2.size()-1; i >= 0; --i) {
            while(monoStack.size() && monoStack.top() <= nums2[i]) {
                monoStack.pop();
            }
            nextGreaterElement[i] = monoStack.empty() ? -1 : monoStack.top();
            monoStack.push(nums2[i]);
        }
        vector<int> ans;
        for(auto e : nums1) {
            ans.push_back(nextGreaterElement[pos[e]]);
        }
        return ans;
    }
};

November LeetCoding Challenge 3

Description

Consecutive Characters

Given a string s, the power of the string is the maximum length of a non-empty substring that contains only one unique character.

Return the power of the string.

Example 1:

Input: s = "leetcode"
Output: 2
Explanation: The substring "ee" is of length 2 with the character 'e' only.

Example 2:

Input: s = "abbcccddddeeeeedcba"
Output: 5
Explanation: The substring "eeeee" is of length 5 with the character 'e' only.

Example 3:

Input: s = "triplepillooooow"
Output: 5

Example 4:

Input: s = "hooraaaaaaaaaaay"
Output: 11

Example 5:

Input: s = "tourist"
Output: 1

Constraints:

• 1 <= s.length <= 500
• s contains only lowercase English letters.

Solution

nothing to say

class Solution {
public:
    int maxPower(string s) {
        int ans = 0, cnt = 0;
        char cur = '?';
        for(auto c : s) {
            if(c != cur) {
                ans = max(cnt, ans);
                cur = c;
                cnt = 1;
            } else {
                cnt += 1;
            }
        }
        ans = max(cnt, ans);
        return ans;
    }
};